Had to be compatible with both languages. The only time you'd use the form with void is in a header that The general rule, in C++, is to just write: extern void func() C++ then added this special case for reasons of I think most of us just want another Prototype game with modern tech behind it. I wouldn't even mind just the original story done to a higher quality. So it also added: extern void func(void) ДЄs a special way of saying that the function doesn't take any But make prototype 3 an interquel between 1 & 2, deal with Pariah that way and actually give a good reason for Mercer going insane. Here are 3 reasons cheap prototyping solutions may not meet your production. But to avoidД«reaking existing code, it didn't require them, and treated extern void func() ДЄs before: a function taking an unknown number and types of Its not uncommon for manufacturers to source prototype development overseas. AndДeclared a function which had no parameters calling it withДЄrguments was an error, as was defining it with arguments.Д¬ then added function prototypes from C++. You'd write: extern void func() Д¬++ added function prototypes, and made the above illegal. If the answer to 1 above is that it is a safe thing to do, then does your answer change if func() is implemented in some language other than C?Д¬ did not originally have function prototypes. can one assume that the ABI will reliably ensure that the invocation of func() in main() will put the three parameters in the right places (registers, stack, whatever) for func() to find them? When I run this program, I get, as expected the output 1, 2, 3. Here is func.c, which contains main() #include ДЄnd here is func1.c which contains the function func() #include So, I did this, I made a test to verify that this works and I'm not surprised that it does. Is that func is a function returning nothing (void) and whose parameters are unknown at this time.ДЇurther they have opined that one could make this declaration and then invoke the function with some arguments such as: func (1, 2, 3) Several have answered that question and opined that in C, the meaning of the function prototype void func () This question is an offshoot of `f(void)` meaning no parameters in C++11 or C?

No prototype 3